A messenger walks 10 m north, then 6 m east, then 2 m south. How far is he from the starting point?

Correct answer: D. 10 m

Net movement: 10 − 2 = 8 m north and 6 m east. The distance is √(8² + 6²) = √100 = 10 m, to the northeast. Combine opposite directions first, then use the Pythagorean theorem.

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Answer and explanation

The correct answer is D. 10 m

Net movement: 10 − 2 = 8 m north and 6 m east. The distance is √(8² + 6²) = √100 = 10 m, to the northeast. Combine opposite directions first, then use the Pythagorean theorem.

Topic: Direction and Distance MCQs · Subject: Analytical Ability